Seymour Lake, VT
Seymour Lake is a lake in Orleans County, Vermont. It has an elevation of 1,279 feet.
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Degrees Minutes Seconds:
Latitude: 445349N
Longitude: 0715856W
Decimal Degrees:
Latitude: 44.89694
Longitude: -71.98222
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Public photos on Flickr that are tagged with Seymour Lake Vermont will appear below. If no photos appear, no results found.
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